x^2+2x-40000=0

Solution for x^2+2x-40000=0 equation:

x^2+2x-40000=0

a = 1; b = 2; c = -40000;
Δ = b2-4ac
Δ = 22-4·1·(-40000)
Δ = 160004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160004}=\sqrt{4*40001}=\sqrt{4}*\sqrt{40001}=2\sqrt{40001}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{40001}}{2*1}=\frac{-2-2\sqrt{40001}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{40001}}{2*1}=\frac{-2+2\sqrt{40001}}{2}
$